(X-2)(2x)=x^2

Solution for (X-2)(2x)=x^2 equation:

(X-2)(2X)=X^2

We move all terms to the left:

(X-2)(2X)-(X^2)=0

determiningTheFunctionDomain
-X^2+(X-2)2X=0

We add all the numbers together, and all the variables

-1X^2+(X-2)2X=0

We multiply parentheses

-1X^2+2X^2-4X=0

We add all the numbers together, and all the variables

X^2-4X=0

a = 1; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·1·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*1}=\frac{0}{2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*1}=\frac{8}{2}
=4
$